0=0.5x^2-4x+6

Solution for 0=0.5x^2-4x+6 equation:

0=0.5x^2-4x+6

We move all terms to the left:

0-(0.5x^2-4x+6)=0

We add all the numbers together, and all the variables

-(0.5x^2-4x+6)=0

We get rid of parentheses

-0.5x^2+4x-6=0

a = -0.5; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·(-0.5)·(-6)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2}{2*-0.5}=\frac{-6}{-1}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2}{2*-0.5}=\frac{-2}{-1}
=+2
$